Question

calcule: (4^-1+2^-3)^-1??

Answer 1

Olá.

$\mathsf{(4^{-1}+2^{-3})^{-1}=\left(\dfrac{1}{4}+\dfrac{1}{2^3}\right)^{-1}=\left(\dfrac{1}{4}+\dfrac{1}{8}\right)^{-1}=\left(\dfrac{2\cdot1+1}{8}\right)^{-1}=}\\\\\mathsf{\left(\dfrac{3}{8}\right)^{-1}=\boxed{\mathsf{\left(\dfrac{8}{3}\right)}}}$

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Bons estudos.