Calcule (3x + 2) . (x - 3) = (3a2 + 2a + 4) . (-a - 3) = (-2x +5) . (6x2 + 4x
Soluções para a tarefa
Resposta:
(3 x + 2 ) × (x- 3 ) =
3x.x +3x.-3 +2.x +2.-3 =
3x² -9x +2x -6 =
3x² -7x -6 ) (3a² + 2 a + 4 )× (- a -3 ) =
3a².-a +3a².-3 +2a.-1 +2a.-3 +4.-a +4.-3 =
9x³ -9a² -2a -6a -4a -12 =
9x³ -9a² -12a -12 +( -2 x + 5 ) × (6 x² + 4 x + 3) =
-2x.6x² -2x.4x -1x.3 +5.6x² +5.4x +5.3=
-12x³ -8x² -3x +30x² +20x +15 =
-12x³ -8x² +30x² -3x +20x +15 =
-12x² +22x² +17x +15 ) ( + 5 x² + 2 x -1 ) × ( x - 3 ) =
5x².x +5x².-3 +2x.x +2x.-3 -1.x -1.-3 =
5x³ -15x² +2x² -6x +1x +3
5x³ -13x² -5x +4 ) (a + b ) × (a - b ) =
a.a +a.-b +b.a +b.-b =
a² -ab +ab -b² = -ab +ab se cancelam
a² - b² ( demorei um tenpin pra faze isso o-o ( me agradeça dps rsrs )