Question

calcule 3^×+3^-× para x=2

Answer 1

$3^{x} + 3^{-x} Quando~x=2 \\ 3^{2} + 3^{-2} \\ 9 + (\frac{1}{3})^{2} \\ 9 + \frac{1}{9} \\ \frac{81 + 1}{9} \\ \\ R = \frac{82}{9}$

Answer 2

vamos lá.

3^x + 3^(-x) =

3² + 1/3² =


9 + 1/9 =


82/9


att Jhonny ♥