Question

calcule -3-(-2+3[-4+(-1+3)]^2 -1)-1

Answer 1

$-3-(-2+3[-4+(-1+3)]^2 -1)-1$

$-3-(-2+3[-4+2]^2-1)-1$

$-3-(-2+3[-2]^2-1)-1$

$-3-(-2+3*4-1)-1$

$-3-(-2+12-1)-1$

$-3-(10-1)-1$

$-3-9-1$

$-12-1$

$-13$

Answer 2

-3-(-2+3[-4+(-1+3)]^2 -1)-1
-3 - {-2+3.[-4+(2)]^2 - 1} - 1
- 4 - {- 2 + 3.[-2]^2 - 1}
- 4 - {- 2 + 3.4 - 1}
- 4 - {- 3 + 12}
- 4 - {9}
- 4 - 9
= - 13