Question

Calcule 25 - (-5)^2+ 3^1+ 4^0+ 2^-1

Answer 1

Olá!

Calcule:

$25-(-5)^{2}+3^{1}+4^{0}+2^{-1}\\ \\ 25-25+3+1+\dfrac{1}{2} \\ \\ \\ 25-25+3+1+\dfrac{1}{2}\\ \\ \\ \dfrac{4}{1} +\dfrac{1}{2}~~=~~\dfrac{8+1}{2} ~~=~~ \dfrac{9}{2} \\ \\ \\ \boxed{4,5}$

:)

Answer 2

Oie, Td Bom?!

$= 25 - ( - 5) {}^{2} + 3 {}^{1} + 4 {}^{0} + 2 {}^{ - 1}$

$= 25 - 25 + 3 + 1 + \frac{1}{2}$

$= 3 + 1 + \frac{1}{2}$

$= 4 + \frac{1}{2}$

$= \frac{8 + 1}{2}$

$= \frac{9}{2}$

$= 4,5$

Att. Makaveli1996