Matemática, perguntado por animoanonimo98, 5 meses atrás

Calcule:

1)3x – 6 – 2x

2) 5 . 4x²

3)21x³ : 3x

4)10x . 10y . 10x³

5) 35x : 5x4

6) 8y² . 7y–7​

Soluções para a tarefa

Respondido por josefinadacosta2
2

Resposta:

1)x-6

2)5.16x²

x=80

3)9261x³:3

x=3087

4)10x.10x.1000x³

x=100×1000

x=100000

5)35x:20

x=1,75

6)64y².0

y=64

Respondido por Usuário anônimo
1

꧁Hello, how are you?꧂

1 ) \:  \: 3x - 6 - 2x \\ (3 - 2)x \\ 1x \\ x \\ x - 6

2) \:  \: 5 \times 4x {}^{2}  \\ 20x {}^{2}

3) \:  \: 21x {}^{3}  \div 3x \\ 7x {}^{3} \times x \\ 7x {}^{3}  \times x {}^{1}   \\ 7x {}^{ 3 + 1}  \\ 7x {}^{4}

4) \:  \: 10x \times 10y \times 10x {}^{3}  \\ 1000xyx {}^{3}  \\ 1000x {}^{1} yx {}^{ 3}  \\ 1000x {}^{1 + 3} y \\ 1000x {}^{4} y \\

5) \:  \: 35x \div 5x4 \\ 7x \times x \times 4 \\ 28x \times x \\ 28x {}^{1}  \times x \\ 28x {}^{1}  \times  {}^{} x {}^{1}  \\ 28x {}^{1 + 1}  \\ 28x {}^{2}  \\

6) \:  \: 8y {}^{2}  \times 7y - 7 \\ 56y {}^{2}  \times y - 7 \\ 56y {}^{3}  - 7 \\ 7(8y {}^{3}  - 1) \\ 2 {}^{3} y {}^{3}  - 1 \\ 2 {}^{3} y {}^{3}  - 1 {}^{3}  \\ (2y) {}^{3}  - 1 {}^{3}  \\ (2y - 1) \times ((2y) {}^{2}  + 2y \times 1 + 1 {}^{2} ) \\ (2y - 1) \times (4y {}^{2}  + 2y \times 1 + 1 {}^{2} ) \\ (2y - 1) \times (4y {}^{2}  + 2y + 1 {}^{2} ) \\ (2y - 1) \times (4y {}^{2}  + 2y + 1) \\

Demorei, mas terminei... ;-;

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