Question

Calcule
1) 2^3+4^1.3^-2=

2) 6^3-2^-2+31=

Answer 1

Olá!

a) 
$2^{3} + 4^{1}. 3^{-2} \\ \\ 8 +4. \frac{1}{ 3^{2} } \\ \\ 8+4. \frac{1}{9} \\ \\ 8+ \frac{4}{9} \\ \\ \frac{8.9}{1.9} + \frac{4}{9} \\ \\ \frac{72+4}{9} = \frac{76}{9}$

b) 
$6^{3}- 2^{-2} + 31 \\ \\ 216 - \frac{1}{ 2^{2} } + 31 \\ \\ 216 - \frac{1}{4} + 31 \\ \\ 216+31- \frac{1}{4} \\ \\ 247- \frac{1}{4} \\ \\ \frac{247.4}{1.4} - \frac{1}{4} \\ \\ \frac{988}{4} - \frac{1}{4} = \frac{987}{4}$

Bons estudos.