Question

calcular X e Y na figura a seguir:​

Answer 1

Explicação passo-a-passo:

• $\sf cos~60^{\circ}=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf \dfrac{1}{2}=\dfrac{x}{6}$

$\sf 2x=6\cdot1$

$\sf 2x=6$

$\sf x=\dfrac{6}{2}$

$\sf \red{x=3~m}$

• $\sf sen~60^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{y}{6}$

$\sf 2y=6\sqrt{3}$

$\sf y=\dfrac{6\sqrt{3}}{2}$

$\sf \red{y=3\sqrt{3}~m}$