Question

Calcular x aplicando o teorema de Pitágoras:

Answer 1

Resposta:

Segue as respostas:

A)

$4x + 3x = 20 \\ 7x = 20 \\ x = 20 \div 7 \\ x = 2.75$

B)

$6 + \sqrt[3]{5} = x \\ x = \sqrt[3]{ - 5} - 6 \\ x = - 21 \\ x = - 21 \div 1 \\ x = - 21$

C)

$x + x = 6 \\ 2x = 6 \\ x = 6 \div 2 \\ x = 3$

D)

$\sqrt{17} + \sqrt{26} = x \\ x = 4.123 - 5 \\ x = 0.8 \\ x = 0.8 \div x \\ x = 0.8$