Question

calcular o valor de h(x)=4x²-6x+3,para:
A) x= -2
B) x= 0
C) x= 3

Answer 1

h(x)=4x²-6x+3

a) x = - 2
h(-2) = 4.(-2)² - 6(-2) + 3
h(-2) = 4.4 + 12 + 3
h(-2) = 16 + 15
h(-2) = 31

b) x = 0
h(0) = 4.0² - 6.0 + 3
h(0) = 3

c) x = 3
h(3) = 4.(3)² - 6.3 + 3
h(3) = 4.9 - 18 + 3
h(3) = 36 - 15
h(3) = 21

Answer 2

A) h(-2)=4.(-2)²-6.(-2)+3
     h(-2)=4.4+12+3
     h(-2)=16+15
     h(-2)=31

B) h(0)=4.0²-6.0+3
     h(0)=0-0+3
     h(0)=3

C) h(3)=4.3²-6.3+3
     h(3)=4.9-18+3
     h(3)=36-15
     h(3)=21