Matemática, perguntado por fernandogamelo74, 11 meses atrás

calcular o log(18x+10)-log(x+5)=1


fernandogamelo74: log(18x+10)-log/x+5)=1
fernandogamelo74: fernando gamelo João

Soluções para a tarefa

Respondido por GeBEfte
2

Utilizando a propriedade do logaritmo do quociente, temos:

log\,(18x+10)~-~log\,(x+5)~=~1\\\\\\log\,\left(\frac{18x+10}{x+5}\right)~=~1\\\\\\\frac{18x+10}{x+5}~=~10^1\\\\\\18x+10~=~(x+5)~.~10\\\\\\18x+10~=~10x+50\\\\\\18x-10x~=~50-10\\\\\\8x~=~40\\\\\\x~=~\frac{40}{8}\\\\\\\boxed{x~=~5}

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