Question

calcular o 10º termo da PG (3,6,12...)

Answer 1

primeiro calculamos a razão

q = a2/a1
q = 6/3
q = 2

an = a1 . q^n-1
a10 = 3.2^10-1
a10 = 3.2^9
a10 = 3.512
a10 = 1536

Answer 2

$\boxed{a_n = a_1*q^n^-^1}\\\\ q = \frac{a_2}{a_1} = \frac{6}{3} = 2\\\\ a_1_0 = 3*2^9$

$a_1_0 = 3*512\\\\ \boxed{a_1_0 =1536}$