Question

calcular as geratrizes das seguintes dízimas periódicas compostas

a) 0,34848...
b) 0,4588...
c) 0,344...
d) 3,566...
e) 7,2355...
f) 12,3444...
g) 15,6222...
h) 20,7888...

por favor​

Answer 1

a) 0,348 48..= 348-3/990 =345/990= 23/66

b) 0,458 8... = 458-45/900= 413/900

c) 0,34 4... = 34-3/90= 31/90

d) 3,56 6...= 356-35/90 = 321/90= 107/30

e) 7,235 5...=7235-723/900=6512/900

f) 12,34 4 4..=1234-123/90= 1111/90

g) 15,62 22...= 1562-156/90= 1406/90

h) 20,78 88...= 2078-207/90 = 1871/90

Answer 2

Resposta:

a) 0,348 48..= 348-3/990 =345/990= 23/66

b) 0,458 8... = 458-45/900= 413/900

c) 0,34 4... = 34-3/90= 31/90

d) 3,56 6...= 356-35/90 = 321/90= 107/30

e) 7,235 5...=7235-723/900=6512/900

f) 12,34 4 4..=1234-123/90= 1111/90

g) 15,62 22...= 1562-156/90= 1406/90

h) 20,78 88...= 2078-207/90 = 1871/90

Explicação passo-a-passo: