Question

calcular as coordenadas da vértice da parábola y=2x²+2x-4 ​

Answer 1

$\boxed{\boxed{V\left(-\dfrac{1}{2}, -\dfrac{9}{2}\right)}}\\\\\\y = 2x^2 + 2x - 4 \\ \\ a = 2\\ b = 2 \\ c = -4 \\\\x_v = -\dfrac{b}{2a} = -\dfrac{2}{2 \cdot 2} = -\dfrac{2}{4} = -\dfrac{1}{2}\\\\\\y_v = -\dfrac{\Delta}{4a} = -\dfrac{b^2-4ac}{4a} = -\dfrac{2^2-4\cdot2\cdot(-4)}{4 \cdot 2} = -\dfrac{4-8 \cdot (-4)}{8} = -\dfrac{4+32}{8}=-\dfrac{36}{8}=-\dfrac{9}{2}$

Answer 2

Resposta:

(-1/2, -9/2)

Explicação passo-a-passo:

Olá!

Para calcular o vértice da parábola, usaremos as fórmulas do X e do Y do vértice:

Xv= -b/2a

Xv= -2/2.2

Xv= -1/2 ou -0,5

Yv= -∆/4a

∆=b²-4ac

∆=36

Yv=-36/4.2

Yv= -9/2 ou -4,5

V= (-1/2, -9/2)

Espero ter ajudado