Question

Calcular a medida do lado
BC, de um triângulo ABC, sabendo-se que:

=60⁰,


= 45⁰
e AB=2m.

Answer 1

verifica se du pra entender...........................................................................

Answer 2

$cos60^o= \frac{BD}{2m} \\ \\ \frac{1}{2}= \frac{BD}{2} \\ \\ BD=1$



$sen60^o= \frac{h}{2m} \\ \\ \frac{ \sqrt{3} }{2}= \frac{h}{2} \\ \\ h= \sqrt{3}$



$tan45^o= \frac{h}{DC} \\ \\ 1= \frac{ \sqrt{3}}{DC} \\ \\ DC= \sqrt{3}$



a = BD + DC

a = 1 + √3.