Question

calcular a integral $\int$ (x³-6x²+4x-2) dx

Answer 1

Olá, Paloma.

$\int x\³-6x\²+4x-2\ dx=\\\\=\frac{x^4}4-6\cdot\frac{x^3}3+4\cdot\frac{x^2}2-2x=\\\\=\frac{x^4}4-2x^3+2x^2-2x$