Question

Calcular a integral definida abaixo

Answer 1

∫ 8t²  + cos (t)  dt

                        π/2
=8t³/3 + sen (t) ]
                       -π/2

= (8/3)  * (π/2)³  + sen π/2    -  (8/3) * (-π/2)³  - sen(-π/2)

***sen( -π/2) =-sen (π/2)

= (8/3)  * (π/2)³  + sen π/2    -  (8/3) * (-π/2)³  - (-sen (π/2))

= (8/3)  * (π³/8)  + sen π/2    -  (8/3) * (-π³/8) + sen π/2  

= (8/3)  * (π³/8)  + sen π/2    + (8/3) * (π³/8) + sen π/2  

=(16/3)  * (π³/8)  +2 * sen π/2

=(2π³/3)    + 2   é a resposta