Question

Calcular a derivada de :
2x² . raiz de x

Answer 1

Oi :) 
Fiz no passo a passo: 

$y=2x^2. \sqrt{x} \\ \\ y'= \frac{d}{dx} (2x^2). \sqrt{x} +2x^2 .\frac{d}{dx}(\sqrt{x}) \\ \\ y'= 4x. \sqrt{x} +2x^2 .\frac{1}{2 \sqrt{x} } \\ \\ y'= 4x. \sqrt{x} +\frac{x^2}{\sqrt{x} } \\ \\ y'= \frac{4x \sqrt{x}. \sqrt{x}+x^2}{\sqrt{x} } \\ \\ y'= \frac{4x .x+x^2}{\sqrt{x} } \\ \\ y'= \frac{4x^2+x^2}{\sqrt{x} } \\ \\ y'= \frac{5x^2}{\sqrt{x} } \\ \\ y'=5x^{ \frac{3}{2} } \\ \\ y'=5 \sqrt{x^3}$