Question

calcular a derivada de(2x2 −3x+1)
6

Answer 1

$y=(2x^2-3x+1)^6\\ \\ u=2x^2-3x+1\\ \\ \frac{dy}{dx}=\frac{dy}{du}.\frac{du}{dx}=6u^5.(4x-3)=6(2x^2-3x+1)^5.(4x-3)$

Answer 2

$y=(2x^{2}-3x+1)^6= \\ y'=6(2.2x^1-3x)^5 \\ y'=6(4x-3x)^5$