Question

calcular a deiravada de sen $\sqrt{x}$

Answer 1

$f(x) = sen \sqrt{x}$

$g(u) = senu =\ \textgreater \ g'(u) = cosu$

$u(x) = \sqrt{x} =\ \textgreater \ u(x) = x^{ \frac{1}{2} } =\ \textgreater \ u'(x) = \frac{1}{2 \sqrt{x} }$

$g'(x) = cos \sqrt{x}$

f'(x) = g'(x) . u'(x)

$f'(x) = \dfrac{1}{2 \sqrt{x} } .cos \sqrt{x}$