Question

calcular: 2^0 + (-2)^6 * 4^-2 - (-2)^3 - (1/4)^-1
a) 2
b) 4
c) 6
d) 8

Answer 1

Olá Estudante!

➡️ Bora Ver A Explicação:

$\huge {\boxed {\sf \bf 2^0 + \left ( -2 \right )^6 \cdot 4^{-2} - \left ( -2 \right )^3 - \left (\cfrac{1}{4} \right ) ^{-1} }}$

$\huge {\boxed {\sf \bf 1+ 64 \cdot \cfrac{1}{16} - \left ( -8 \right ) - \cfrac{4}{1} }}$

$\huge {\boxed {\sf \bf 1+ \cfrac{64}{16} + 8 - 4 }}$

$\huge {\boxed {\sf \bf 1+4+ 8 - 4}}$

$\huge {\boxed {\sf \bf 9}}$

• Att. MatiasHP