Question

calculando corretamente as raízes da equação x ao quadrado+4x+5=0, encontramos valores complexos para as raízes

Answer 1

$x^2+4x+5=0$

a=1  b=4   c=5

$delta=4^2-4.1.5=16-20=-4 \\ \\ \sqrt{delta} = \sqrt{-4} =4i \\ \\ \\ x_{1} = \frac{-4+4i}{2} =-2+2i \\ \\ \\ x_{2} = \frac{-4-4i}{2} =-2-2i$

Answer 2

Calcular o valor de Delta (Δ)

Δ=b²−4ac
Δ=4²−4⋅1⋅5
Δ=16−20
Δ=−4

====

Por Bhaskara:

$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}$

$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\x = \dfrac{-4 \pm \sqrt{-4}}{2*1}\\ \\ \\x = \dfrac{-4 \pm 2.i}{2}\\ \\ \\x' = \dfrac{-4 + 2.i}{2}\\ \\ \\x' = -2i\\ \\ \\x'' = \dfrac{-4 - 2.i}{2}\\ \\ \\ x'' = -2i$

S = {-2i, -2i }