Calculando a área de um pentagono regular do lado 4 m, encontramos a área:
Soluções para a tarefa
Respondido por
1
vamos usar a area do triangulo
A = b x h
.......____
...........2
b = 4
alpha = 360¤ / 5
alpha = 72¤
alpha = 36¤
____
.....2
tg 36¤ = (b/2)
................____
....................h
tg 36¤ = (4:2)
................____
....................h
h = (4/2)
......____
.......tg36¤
h = (4/2)
......____
......0,727
h =......2
......._____
.......0,727
h = 2,7624cm
h = 2,76cm
A area do triangulo b =4cm e h = 2,76cm
A = b x h
.......____
...........2
A = 4cm x 2,76
......._________
..............2
A = 11,04cm^2
.......____
............2
A = 5,52 cm^2
A area do pentagono e :
A = 5 x 5,52
A = 27,60 cm^2.
Resposta a area do tpentagono e 27,6cm^2...............
A = b x h
.......____
...........2
b = 4
alpha = 360¤ / 5
alpha = 72¤
alpha = 36¤
____
.....2
tg 36¤ = (b/2)
................____
....................h
tg 36¤ = (4:2)
................____
....................h
h = (4/2)
......____
.......tg36¤
h = (4/2)
......____
......0,727
h =......2
......._____
.......0,727
h = 2,7624cm
h = 2,76cm
A area do triangulo b =4cm e h = 2,76cm
A = b x h
.......____
...........2
A = 4cm x 2,76
......._________
..............2
A = 11,04cm^2
.......____
............2
A = 5,52 cm^2
A area do pentagono e :
A = 5 x 5,52
A = 27,60 cm^2.
Resposta a area do tpentagono e 27,6cm^2...............
Perguntas interessantes