Question

cal
Calcule o seno coseno e a tangente de 35°,60° e 45°

Answer 1

Pela Foto da Questão 24 ) 

30º

$\boxed{Sen30=\frac{\frac{l}{2}}{l}=\frac{l}{2}.\frac{1}{l}=\frac{1}{2}\\}\\\\\boxed{Cos30=\frac{\frac{l\sqrt{}3}{2}}{l}=\frac{l\sqrt{3}}{2}\frac{1}{l}=\frac{l\sqrt{3}}{2}}\\\\\boxed{tg30=\frac{sen30}{cos30}=\frac{\frac{1}{2}}{\frac{l\sqrt{3}}{2}}=\frac{1}{2}.\frac{2}{l\sqrt{3}}=\frac{\sqrt{3}}{3}}$

45º 

$\boxed{sen45=cos45=\frac{l\sqrt{2}}{2}}\\\\\\\boxed{tg45=\frac{sen45}{cos45}=1}$

60º

$\boxed{Sen60=\frac{\frac{l\sqrt{3}}{2}}{l}=\frac{\sqrt{3}}{2}}\\\\\boxed{cos60=\frac{\frac{l}{2}}{l}=\frac{1}{2}}\\\\\boxed{tg60=\frac{sen60}{cos60}=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\sqrt{3}}$