Question

cacule o numero de mols 200g c12 h22 oh​

Answer 1

n (C₁₂H₂₂OH) = ?

m (C₁₂H₂₂OH) = 200g

M (C₁₂H₂₂OH) = 12×12,01 + 22×1,01 + 16 + 1,01 = 183,35 g/mol

M = m/n ⇔ n = m÷M ⇔

             ⇔ n = 200÷183,35 ⇔

             ⇔ n = 1,09 mol