Question

C= [cij]3x3 / cij = { i² + j², se i = j
                           3i - 2j, se i é diferente de j

Answer 1

$\begin{bmatrix} x_{11} & x_{12} & x_{13} \\ x_{21} & x_{22} & x_{23} \\ x_{31} & x_{32} & x_{33} \end{bmatrix}\\\\ x_{11} = 1^{2} + 1^{2} = 2\\ x_{22} = 2^{2} + 2^{2} = 8\\ x_{33} = 3^{2} + 3^{2} = 18\\ x_{12} = 3*1 - 2*2 = -1\\ x_{13} = 3*1 - 2*3 = -2\\ x_{31} = 3*3 - 2*1 = 7\\ x_{21} = 3*2 - 2*1 = 4\\ x_{23} = 3*2 - 2*3 = 0\\ x_{32} = 3*3 - 2*2 = 5\\\\ \begin{bmatrix} 2& -1 &-2 \\ 4& 8 & 0\\ 7&5 &18 \end{bmatrix}$