Question

c) C(cij) 2x2, com cij = i2+j2 me ajudem help!​

Answer 1

$c_{11}={1}^{2}+{1}^{2}=1+1=2\\c_{12}={1}^{2}+{2}^{2}=1+4=5\\c_{21}={2}^{2}+{1}^{2}=4+1=5\\c_{22}={2}^{2}+{2}^{2}=4+4=8$

$\huge\mathtt{C=\begin{bmatrix}2&5\\5&8\end{bmatrix}}$

Answer 2

Resposta:

Explicação passo-a-passo:

C) C(cij) 2x2, com cij = i^2+j^2

2 linhas e 2 colunas

C

=

[c11 c12]

[c21 c22]

cij = i^2+j^2

c11 = 1^2+1^2 = 1+1 = 2

c12 = 1^2 + 2^2 = 1 + 4 = 5

c21 = 2^2 + 1^2 = 4 + 1 = 5

c22 = 2^2+2^2 = 4+4= 8

R :

C =

[2 5]

[5 8]