Question

C = [aij]3×3, tal que aij = i + j​

Answer 1

Explicação passo-a-passo:

$C=\left[\begin{array}{ccc}a_{11} &a_{12}&a_{13}\\a_{21} &a_{22}&a_{23}\\a_{31} &a_{32}&a_{33}\end{array}\right]$

Temos que $a_{ij} =i+j$.

$\\\\a_{11} =1+1=2\\a_{12} =1+2=3\\a_{13} =1+3=4\\a_{21} =2+1=3\\a_{22} =2+2=4\\a_{23} =2+3=5\\a_{31} =3+1=4\\a_{32} =3+2=5\\a_{33} =3+3=6$

$C=\left[\begin{array}{ccc}2&3&4\\3&4&5\\4&5&6\end{array}\right]$