Question

c) 6²:(2³+1)x(3² -5 )
d) (7x3²-1):(8²-2x31)

Answer 1

Resposta:

c)$16$

d)31

Explicação passo a passo:

$=6^2\div \left(2^3+1\right)\left(3^2-5\right)\\=6^2\div \:9\cdot \:4\\\\=6^2\div \:9\cdot \:4\\=16\\\\d) \left(7\cdot \:3^2-1\right)\div \left(8^2-2\cdot \:31\right)\\=62\div \left(8^2-2\cdot \:31\right)\\\\\\\\=62\div \:2\\=31$