Question

binomio de newton ( x-y)³

Answer 1

(x-y)^3 = (x-y)^2 * (x-y) ->
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(x-y)^2 = (x-y)*(x-y) = x^2 -xy -xy + y^2 = x^2 -2xy + y^2
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-> (x-y)^3 = (x^2-2xy+y^2) *(x-y) = x^3 -2x^2y + xy^2 -x^2y + 2xy^2 - y^3=
                = x^3 -3x^2y + 3xy^2 - y^3

Resultado: x³ - 3x²y + 3xy² - y³