Question

Bhaskara: x^2+3-4=0
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Answer 1

Resposta:

S = { - 1, 1 }

Explicação passo a passo:

x² + 3 - 4 = 0

x² - 1 = 0

$x=\frac{-b+/-\sqrt{b^{2} }-4ac }{2a}$

$x=\frac{-0+/-\sqrt{0^{2} } - 4.1.(-1)}{2.1}$

$x=\frac{0+/-\sqrt{0+4} }{2}$

$x=\frac{0+/-\sqrt{4} }{2}$

$x=\frac{0+/-2}{2}$

$x'=\frac{0-2}{2}$

$x'=\frac{-2}{2}$

x' = - 1

$x''=\frac{0+2}{2}$

$x''=\frac{2}{2}$

x'' = 1

S = { - 1, 1 }