Question

Bhaskara
Resolva :
(x+3)²=1

Answer 1

$(x+3)^2 = 1 \\ x^2 + 6x + 9 = 1 \\ x^2 + 6x + 9 - 1 = 0 \\ \\ x^2 + 6x + 8 = 0 \\ \\ a = 1 \\ b = 6 \\ c = 8 \\ \\ x = \frac{-b\pm \sqrt{b^2-4.a.c} }{2.a} \\ \\ x = \frac{-6\pm \sqrt{6^2-4.1.8} }{2.1} \\ \\ x = \frac{-6\pm \sqrt{36-32} }{2} \\ \\ x = \frac{-6\pm \sqrt{4} }{2} \\ \\ x = \frac{-6\pm2}{2} \\ \\ \\ x' = \frac{-6+2}{2} \rightarrow x' = \frac{-4}{2} \rightarrow x' = -2 \\ \\ x'' = \frac{-6-2}{2} \rightarrow x'' = \frac{-8}{2} \rightarrow x'' = -4$

Raízes da equação:

x' = -2
x'' = -4