Question

Bhaskara (por favor)

-x^2-x+30=0

Answer 1

$- {x}^{2} - x + 30 = 0 \: (x - 1)\\ {x}^{2} + x - 30 = 0 \\ \\ delta = {b}^{2} - 4ac \\ delta = (1 {)}^{2} - 4(1)( - 30) \\ delta = 1 + 120 \\ delta = 121 \\ \\ \frac{ - b + ou - \sqrt{delta} }{2a} \\ \\ \frac{ - (1) + 11}{2(1)} = \frac{ - 1 + 11}{2} = \frac{10}{2} = 5 \\ \\ ou \\ \\ \frac{ - (1) - 11}{2(1)} = \frac{ - 1 - 11}{2} = \frac{ - 12}{2} = - 6$

Resposta final: x = 5 ou -6