Question

bhaskara de 4x²-20x+25=0

Answer 1

Δ= (-20²)-4.4.25
Δ=400-400
Δ=0
x=-(-20)+- √0/2.4
x=20/8
x=2,5
formula de bhaskara: -b+-√Δ=b²-4.ac/2.a

Answer 2

delta = b^ -4 ×a×c
(-20)^ - 4 ×4×25
400 - 400= 0

bhaskara = -b +/- ( raiz ) delta
____________________
2a

-(-20) +/- (raiz de 0)
______________________
2 ×4


20 +/- (raiz de 0)
___________________
8

20
___ = 2,5
8