Question

Baseado em estudos anteriores, calcule as potências: a) (+ 2 /3 ) 2 = b) (− 1 /3 ) 0 = c) (+ 2 /3 ) −2 = d) (+ 1 /6 ) 1 =

Answer 1

Resposta:

Nao entendi sua pergunta

Answer 2

$a)\ \Big(+\frac{2}{3} \Big)^2 =\Big(+\frac{2}{3} \Big)\cdot\Big(+\frac{2}{3} \Big)=\frac{4}{9} \\\\b)\ \Big(-\frac{1}{3}\Big)^0 = 1\\\\c)\ \Big(+\frac{2}{3}\Big)^{-2} = \Big(+\frac{3}{2}\Big)^{2}=\frac{9}{4}\ \\\\d)\ \Big(+\frac{1}{6}\Big)^1 =\frac{1}{6}$