Question

b2_4ac,para a=-5,b=-1ec=6

Answer 1

a = -5
b = -1
c = 6

Δ = b² - 4ac
Δ = (-1)² - 4* (-5) * 6
Δ = 1  + (20 *6)
Δ = 1 + 120
Δ = 121

x = [-b ± √Δ] / 2*a
x = [-(-1) ± √121] / 2*(-5)
x = (1 ± 11) / -10

x₁ = (1+11) / -10
x₁ = 12/ -10
x₁ = - 1,2


x₂ = (1-11) / -10
x₂ = -10 / -10
x₂ = 1

Espero ter ajudado.