Question

b) (x + 3). (x + 4) = 7. (x + 6)​

Answer 1

Resposta:

$x_{1} = \sqrt{30} \\ x_{2} = - \sqrt{30}$

$(x + 3). (x + 4) = 7. (x + 6) \\ {x}^{2} + 4x + 3x + 12 = 7x + 42 \\ {x}^{2} + 7x - 7x = 42 - 12 \\ {x}^{2} = 30 \\ x = + - \sqrt{30 \\}$