Question

b) o trigésimo nono termo da P.A. (40; 27; 14, ...)​

Answer 1

Resposta:

a39=534

Explicação passo-a-passo:

a39=40+(39-1).13

a39=40+(38).13

a39=40+494

a39=534

Answer 2

$> resolucao \\ \\ \geqslant progressao \: aritmetica \\ \\ r = a2 - a1 \\ r = 27 - 40 \\ r = - 13 \\ \\ \\ \geqslant o \: 39 \: termo \: da \: pa \\ \\ an = a1 + (n - 1)r \\ an = 40 + (39 - 1) - 13 \\ an = 40 + 38 \times ( - 13) \\ an = 40 + ( - 494) \\ an = 40 - 494 \\ an = - 454 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$