Question

B= (bij) 3×3, tal que bij= -2+i+j​

Answer 1

Resposta:

B = [ b11   b12   b13

       b21   b22   b23

       b31   b32   b33 ]

bij = -2 + i + j

b11 = -2 + 1 + 1 = 0

b12 = -2 + 1 + 2 = 1

b13 = -2 + 1 + 3 = 2

b21 = -2 + 2 + 1 = 1

b22 = -2 + 2 + 2 = 2

b23 = -2 + 2 + 3 = 3

b31 = -2 + 3 + 1 = 2

b32 = -2 + 3 + 2 = 3

b33 = -2 + 3 + 3 = 4

B = [ 0   1   2

       1   2   3

       2   3   4 ]

Explicação passo-a-passo: