Question

b=(bij)3×3 cujo i²+j​

Answer 1

Explicação passo-a-passo:

B = b11 b12 b13

b21 b22 b23

b31 b32 b33

bij= i² + j

b11 = 1²+1= 1+1=2

b12= 1²+2= 1+2=3

b13= 1²+3= 1+3= 4

b21= 2²+1= 4+1=5

b22= 2²+2= 4+2=6

b23= 2²+3= 4+3= 7

b31= 3²+1= 9+1= 10

b32= 3²+2= 9+2= 11

b33= 3²+3= 9+3= 12

B = 2 3 4

5 6 7

10 11 12