Question

B(bij) 1x6 tal que aij= ( j - i )³​

Answer 1

$\Large\boxed{\begin{array}{l}\sf a_{11}=(1-1)^3=0\\\sf a_{12}=(2-1)^3=1\\\sf a_{13}=(3-1)^3=8\\\sf a_{14}=(4-1)^3=27\\\sf a_{15}=(5-1)^3=64\\\sf a_{16}=(6-1)^3=125\\\\\sf B=\begin{bmatrix}\sf0&\sf1&\sf8&\sf27&\sf64&\sf125\end{bmatrix}\end{array}}$