Question

-b+√b²-4 ac,para a=2 , b= -10 e c= 12

Answer 1

Δ=b²-4.a.c
Δ=(-10)²- 4.2.12
Δ=100-96
Δ=4
x= (-b+- √Δ)÷2a
x=(10+-2)÷2(-10)
x=(10+-2)÷(-20)
$x^{1}$=(10+2)÷-20
$x^{1}$=12÷-20
$x^{1}$=$\frac{12}{-20}$
$x^{2}$=(10-2)÷-20
$x^{2}$=8÷-20
$x^{2}$=$\frac{8}{-20}$