Question

-b+√b²-4.a.c a=2 b=3 c=-2

Answer 1

$-b+ \sqrt{b^2-4.a.c} \\ \\ com \\ a=2 \\ b=3 \\ c=-2 \\ \\ -(3)+ \sqrt{3^2-4(2)(-2)} = \\ \\ -3+ \sqrt{9+16} = \\ \\ -3+ \sqrt{25} = \\ \\ -3+5=\fbox{ +2 }$