Question

b) 2x2-5x +1= 0
me ajudar não estou conseguindo​

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~2x^{2}-5x+1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=2{;}~b=-5~e~c=1\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(2)(1)=25-(8)=17\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{17}}{2(2)}=\frac{5-\sqrt{17}}{4}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{17}}{2(2)}=\frac{5+\sqrt{17}}{4}\\\\S=\{\frac{5-\sqrt{17}}{4},~\frac{5+\sqrt{17}}{4}\}$