Question

ATIVIDADES COM EXERCÍCIOS (Trigonometria)

Answer 1

Explicação passo-a-passo:

a)

${x}^{2} = {9}^{2} + {12}^{2} = > {x}^{2} = 81 + 144 = > {x}^{2} = 225 = > x = \sqrt{225} = > x = 15$

sem B = 12/15 => sem B = 4/5

cos B = 9/15 => cos B = 3/5

tag B = 12/9 => tag B = 4/3

b)

${x}^{2} + {8}^{2} = {16}^{2} => {x}^{2} + 64 = 256 => {x}^{2} = 256 - 64 => {x}^{2} = 192 => x = \sqrt{192} =>x = \sqrt{ {2}^{6}.3} = > x = {2}^{3} \sqrt{3} = > x = 8 \sqrt{3}$

sen C = 8/16 => sen C = 1/2

$cos c = \frac{ 8\sqrt{3} }{16} = > cos c = \frac{ \sqrt{3} }{2}$

$tag c = \frac{8 \sqrt{3} }{8} = > tag c = \sqrt{3}$