Question

Atividade de matrizes

Answer 1

Explicação passo-a-passo:

$\sf X-B=2A$

$\sf X=2A+B$

$\sf X=2\cdot\left[\begin{array}{cc} \sf 2& \sf 7 \\ \sf -1 & \sf 4 \end{array}\right]+\left[\begin{array}{cc} \sf 3& \sf -2 \\ \sf 6 & \sf 0 \end{array}\right]$

$\sf X=\left[\begin{array}{cc} \sf 2\cdot2 & \sf 2\cdot7 \\ \sf 2\cdot(-1) & \sf 2\cdot4 \end{array}\right]+\left[\begin{array}{cc} \sf 3& \sf -2 \\ \sf 6 & \sf 0 \end{array}\right]$

$\sf X=\left[\begin{array}{cc} \sf 4& \sf 14 \\ \sf -2 & \sf 8 \end{array}\right]+\left[\begin{array}{cc} \sf 3& \sf -2 \\ \sf 6 & \sf 0 \end{array}\right]$

$\sf X=\left[\begin{array}{cc} \sf 4+3& \sf 14-2 \\ \sf -2+6 & \sf 8+0 \end{array}\right]$

$\sf X=\left[\begin{array}{cc} \sf 7& \sf 12 \\ \sf 4 & \sf 8 \end{array}\right]$

Letra C