Question

ATIVIDADE DE MATEMÁTICA
CALCULE AS EXPRE
$16 \sqrt{ + {3}^{2} } =$
c)
$\frac{2}{3} + \frac{1}{4} - \frac{1}{2} =$

b)
$( - {2})^{3} - \sqrt{25}$
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Answer 1

Resposta:

a) $16\sqrt{3^2}=16.3=48$

b) $\dfrac{2}{3}+\dfrac{1}{4}-\dfrac{1}{2}=\dfrac{8}{12}+\dfrac{3}{12}-\dfrac{6}{12}=\dfrac{5}{12}$

c) $(-2)^3-\sqrt{25} =-8-5=-13$

Explicação passo-a-passo: