Question

Atividade 2.
a) Escreva uma PA de 8 termos crescente de primeiro termo igual a 10 e razão 8.​

Answer 1

Resposta:

Explicação passo-a-passo:

$a_1=10,\ r=8\\\\ \boxed{a_n=a_k+(n-k)r}\ \therefore\ a_n=a_1+(n-1)r\ \therefore\\\\ a_n=10+(n-1)(8)=10+8n-8\ \therefore\ \boxed{a_n=2(4n+1)}\\\\ a_2=2(8+1)=18\\ a_3=2(12+1)=26\\ a_4=2(16+1)=34\\ a_5=2(20+1)=42\\ a_6=2(24+1)=50\\\\ (a_1,a_2,a_3,a_4,a_5,a_6,\dots)=\boxed{(10,18,26,34,42,50,\dots)}$