Question

ate hoje. ninguém me explica direitinho

Answer 1

x²=64+y²

5²=(19-y)² +3²

25-9=19²-38y+y²

y²-38y+345=0

y'=[38+√(1444 - 1380)]/2 =[38+√(64)]/2 =(38+8)/2 =23

y11=[38-√(1444 - 1380)]/2 =[38-√(64)]/2 =(38-8)/2 =15

x²=64+y²

Se y=23  ==>x²=64+529   ==>x=√593

Se y=15  ==>x²=64+225 ==> x=√289