Question

Associe cada equação na incógnita x à sua solução geral:


me ajuda aí pf ❤️​

Answer 1

Explicação passo-a-passo:

A)

$\sf 6ax-3a=5ax-4$

$\sf 6ax-5ax=3a-4$

$\sf ax=3a-4$

$\sf x=\dfrac{3a-4}{a},~com~a\ne0$

B)

$\sf (x+1)\cdot a=(x-1)\cdot(a+1)$

$\sf ax+a=ax+x-a-1$

$\sf x+ax-ax=a+a+1$

$\sf x=2a+1$

C)

$\sf ax-3a^2=x-a^2$

$\sf ax-x=3a^2-a^2$

$\sf x\cdot(a-1)=2a^2$

$\sf x=\dfrac{2a^2}{a-1},~com~a\ne1$

D)

$\sf 6ax-2a+5x=13ax+2$

$\sf 5x+6ax-13ax=2+2a$

$\sf 5x-7ax=2+2a$

$\sf x\cdot(5-7a)=2+2a$

$\sf x=\dfrac{2+2a}{5-7a},~com~a\ne\dfrac{5}{7}$

Logo:

• A -> III

• B -> IV

• C -> II

• D -> I

Answer 2

Oie, Td Bom?!

■ Resposta: A (III), B (IV), C (II), D (I).

a)

6ax - 3a = 5ax - 4

6ax - 5ax = - 4 + 3a

6ax - 5ax = 3a - 4

ax = 3a - 4

x = [3a - 4]/a , com a ≠ 0

b)

(x + 1)a = (x - 1) . (a + 1)

ax + a = ax + x - a - 1

a = x - a - 1

- x = - a - 1 - a

- x = - 2a - 1

- 1 . (- x) = - 1 . (- 2)a - 1 . (- 1)

x = 2a + 1

c)

ax - 3a² = x - a²

ax - x = - a² + 3a²

ax - x = 3a² - a²

x . (a - 1) = 2a²

x = 2a²/[a - 1] , com a ≠ 1

d)

6ax - 2a + 5x = 13ax + 2

6ax + 5x - 13ax = 2 + 2a

5x + 6ax - 13ax = 2 + 2a

5x - 7ax = 2 + 2a

x . (5 - 7a) = 2 + 2a

x = [2 + 2a]/[5 - 7a] , com a ≠ 5/7.

Att. Makaveli1996